Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.5 Polynomials and Factoring - R.5 Exercise Set - Page 970: 1

Answer

$6t^3(3t^2-2t+1)$

Work Step by Step

The $GCF$ of the terms is $ 6t^3 $ since it is the highest expression that can evenly divide (no remainder) all the given constants. Factoring the $GCF,$ the given expression is equivalent to \begin{array}{l}\require{cancel} 18t^5-12t^4+6t^3 \\\\= 6t^3(3t^2-2t+1) .\end{array}
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