## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$6t^3(3t^2-2t+1)$
The $GCF$ of the terms is $6t^3$ since it is the highest expression that can evenly divide (no remainder) all the given constants. Factoring the $GCF,$ the given expression is equivalent to \begin{array}{l}\require{cancel} 18t^5-12t^4+6t^3 \\\\= 6t^3(3t^2-2t+1) .\end{array}