Answer
$(\displaystyle \frac{1}{2},-5)$
Work Step by Step
Terms containing $y$ are opposite in the additive sense.
Add the equations:
$ 12x=6\qquad$ ... and solve for $x$
$x=\displaystyle \frac{1}{2}$
Substitute into one of the initial equations:
$6x+3y=-12$
$6(\displaystyle \frac{1}{2})+3y=-12$
$3y=-12-3$
$3y=-15$
$y=-5$
Form an ordered pair $(x,y)$ as the solution to the system
$(\displaystyle \frac{1}{2},-5)$
