Answer
$(3,-2)$
Work Step by Step
Isolate $\mathrm{q}$ in eq.$1$
$ 4p-2q=16\qquad$ ... add $2q-16$
$ 4p-16=2q\qquad$ ... divide with 2
$ q=2p-8\qquad$ (*)
Replace $q$ with $2p-8$ in the other equation:
$ 5p+7(2p-8)=1\qquad$ ... and solve for $p$. Simplify
$5p+14p-56=1$
$19p=57$
$p=3$
Now, back-substitute into (*)
$q=2(3)-8=-2$
Form an ordered pair $(p,q)$ as the solution to the system
$(3,-2)$
