Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.2 Solving by Substitution or Elimination - 8.2 Exercise Set - Page 516: 24


$(-\displaystyle \frac{1}{5},-\frac{7}{5})$

Work Step by Step

Isolate $y$ in eq.$2$ $ 2x-y=1\qquad$ ... add $y-1$ $ 2x-1=y\qquad$ ... divide with 2 $ y=2x-1\qquad$ (*) Replace $y$ with $2x-1$ in the other equation: $ 3x-4(2x-1)=5\qquad$ ... and solve for $x$. $3x-8x+4=5=4$ $-5x=1$ $x=-\displaystyle \frac{1}{5}$ Now, back-substitute into (*) $y=2(-\displaystyle \frac{1}{5})-1=-\frac{7}{5}$ Form an ordered pair $(x,y)$ as the solution to the system $(-\displaystyle \frac{1}{5},-\frac{7}{5})$
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