Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(-\displaystyle \frac{1}{5},-\frac{7}{5})$
Isolate $y$ in eq.$2$ $2x-y=1\qquad$ ... add $y-1$ $2x-1=y\qquad$ ... divide with 2 $y=2x-1\qquad$ (*) Replace $y$ with $2x-1$ in the other equation: $3x-4(2x-1)=5\qquad$ ... and solve for $x$. $3x-8x+4=5=4$ $-5x=1$ $x=-\displaystyle \frac{1}{5}$ Now, back-substitute into (*) $y=2(-\displaystyle \frac{1}{5})-1=-\frac{7}{5}$ Form an ordered pair $(x,y)$ as the solution to the system $(-\displaystyle \frac{1}{5},-\frac{7}{5})$