Answer
$(4,-1)$
Work Step by Step
Isolate $x$ in eq.$2$
$-3y+x=7\qquad$ ... add $3y$
$x=7+3y\qquad $(*)
Replace $x$ with $7+3y$ in the other equation:
$ 5(7+3y)+6y=14\qquad$ ... and solve for $y$. Simplify
$35+15y+6y=14$
$ 21y+35=14\qquad$ ... subtract 35
$21y=-21$
$y=-1$
Now, back-substitute into (*)
$x=7+3(-1)=4$
Form an ordered pair $(x,y) $ as the solution to the system
$(4,-1)$
