Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.2 Solving by Substitution or Elimination - 8.2 Exercise Set - Page 516: 13



Work Step by Step

Variable $x$ is isolated in eq.$2$ $x=8-4y\qquad $(*) Replace $x$ with $8-4y$ in the other equation: $ 3(8-4y)+5y=3\qquad$ ... and solve for $y$. Simplify $24-12y+5y=3$ $-7y+24=3\qquad$ ... subtract 24 $-7y=-21\qquad$ ... divide with $(-7)$ $y=3$ Now, back-substitute into (*) $x=8-4(3)=8-12=-4$ Form an ordered pair $(x,y) $ as the solution to the system $(-4,3)$
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