Answer
$(2,0)$
Work Step by Step
Isolate $b$ in eq.$2$
$ 3a-b=6\qquad$ ... add $b-6$
$ 3a-6=b\qquad$ ... divide with 2
$ b=3a-6\qquad$ (*)
Replace $b$ with $3a-6$ in the other equation:
$ 2a+6(3a-6)=4\qquad$ ... and solve for $a$.
$2a+18a-36=4$
$20a=40$
$a=2$
Now, back-substitute into (*)
$b=3(2)-6=0$
Form an ordered pair $(a,b)$ as the solution to the system
$(2,0)$