## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(2,-2)$
Isolate $t$ in eq.$2$ $5s+t=8\qquad$ ... subtract $5s$ $t=8-5s\qquad$(*) Replace $t$ with $8-5s$ in the other equation: $3s-4(8-5s)=14\qquad$ ... and solve for $x$. Simplify $3s-32+20s=14$ $23s-32=14\qquad$ ... add 32 $23s=46\qquad$ ... divide with $23$ $s=2$ Now, back-substitute into (*) $t=8-5(2)=8-10=-2$ Form an ordered pair $(s,t)$ as the solution to the system $(2,-2)$