## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(2,-1)$
Variable y is isolated in eq.1 $y=3-2x\qquad$(*) Replace $y$ with $3-2x$ in the second equation: $3x+(3-2x)=5\qquad$ ... and solve for $x$. Simplify $3x+3-2x=5$ $x+3=5\qquad$ ... subtract 3 $x=2$ Now, back-substitute into (*) $y=3-2(2)=3-4=-1$ Form an ordered pair $(x,y)$ as the solution to the system $(2,-1)$