Chapter 5 - Polynomials and Factoring - 5.2 Factoring Trinomials of the Type x2+bx+c - 5.2 Exercise Set - Page 317: 70

$x=2$

Using the properties of equality, the solution to the given equation, $ \dfrac{1}{3}x-\dfrac{1}{6}=\dfrac{1}{2} ,$ is \begin{array}{l}\require{cancel} 6\left( \dfrac{1}{3}x-\dfrac{1}{6}\right)=\left( \dfrac{1}{2} \right) 6 \\\\ 2(1x)-1(1)=1(3) \\\\ 2x-1=3 \\\\ 2x=3+1 \\\\ 2x=4 \\\\ x=\dfrac{4}{2} \\\\ x=2 .\end{array}