Chapter 5 - Polynomials and Factoring - 5.2 Factoring Trinomials of the Type x2+bx+c - 5.2 Exercise Set - Page 317: 41

$(x+11)(x+9)$

Work Step by Step

The 2 numbers whose product is $ac= 1(99)=99$ and whose sum is $b= 20$ are $\left\{ 11,9 \right\}.$ Using these two numbers to decompose the middle term of the given trinomial, $x^2+20x+99 ,$ then the factored form is \begin{array}{l} x^2+11x+9x+99 \\\\= (x^2+11x)+(9x+99) \\\\= x(x+11)+9(x+11) \\\\= (x+11)(x+9) .\end{array}

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