Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.2 Factoring Trinomials of the Type x2+bx+c - 5.2 Exercise Set - Page 317: 58



Work Step by Step

The 2 numbers whose product is $ac= 1(24)=24 $ and whose sum is $b= -11 $ are $\left\{ -3,-8 \right\}.$ Using these two numbers to decompose the middle term of the given trinomial, $ x^2-11xy+24y^2 ,$ then the factored form is \begin{array}{l} x^2-3xy-8xy+24y^2 \\\\= (x^2-3xy)-(8xy-24y^2) \\\\= x(x-3y)-8y(x-3y) \\\\= (x-3y)(x-8y) .\end{array}
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