## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(t-16)(t-9)$
In decreasing order of exponents, the given expression, $144-25t+t^2 ,$ is equivalent to \begin{array}{l} t^2-25t+144 .\end{array} The 2 numbers whose product is $ac= 1(144)=144$ and whose sum is $b= -25$ are $\left\{ -16,-9 \right\}.$ Using these two numbers to decompose the middle term of the above trinomial, then \begin{array}{l} t^2-16t-9t+144 \\\\= (t^2-16t)-(9t-144) \\\\= t(t-16)-9(t-16) \\\\= (t-16)(t-9) .\end{array}