Answer
$-c^2(c+8)(c-7)$
Work Step by Step
Factoring the negative $GCF=
-c^2
$, the given expression, $
-c^4-c^3+56c^2
,$ is equivalent to
\begin{array}{l}
-c^2(c^2+c-56)
.\end{array}
The 2 numbers whose product is $ac=
1(-56)=-56
$ and whose sum is $b=
1
$ are $\left\{
8,-7
\right\}.$ Using these two numbers to decompose the middle term of the above trinomial, then
\begin{array}{l}
-c^2(c^2+8c-7c-56)
\\\\=
-c^2[(c^2+8c)-(7c+56)]
\\\\=
-c^2[c(c+8)-7(c+8)]
\\\\=
-c^2[(c+8)(c-7)]
\\\\=
-c^2(c+8)(c-7)
.\end{array}