Answer
$-a^2(a+12)(a-11)$
Work Step by Step
Factoring the negative $GCF=
-a^2
$, the given expression, $
-a^4-a^3+132a^2
,$ is equivalent to
\begin{array}{l}
-a^2(a^2+a-132)
.\end{array}
The 2 numbers whose product is $ac=
1(-132)=-132
$ and whose sum is $b=
1
$ are $\left\{
12,-11
\right\}.$ Using these two numbers to decompose the middle term of the above trinomial, then
\begin{array}{l}
-a^2(a^2+12a-11a-132)
\\\\=
-a^2[(a^2+12a)-(11a+132)]
\\\\=
-a^2[a(a+12)-11(a+12)]
\\\\=
-a^2[(a+12)(a-11)]
\\\\=
-a^2(a+12)(a-11)
.\end{array}