## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$9+3t^5+\dfrac{1}{4}t^{10}$
Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $\left( 3+\dfrac{1}{2}t^5 \right)\left( 3+\dfrac{1}{2}t^5 \right)$, is equivalent to \begin{array}{l}\require{cancel} (3)^2+2(3)\left( \dfrac{1}{2}t^5 \right)+\left( \dfrac{1}{2}t^5 \right)^2 \\\\= 9+3t^5+\dfrac{1}{4}t^{10} .\end{array}