Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set - Page 277: 43

Answer

$x^2+6x+9$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ (x+3)^2 $, is equivalent to \begin{array}{l}\require{cancel} (x)^2+2(x)(3)+(3)^2 \\\\= x^2+6x+9 .\end{array}
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