Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 51

Answer

$t^2-\dfrac{9}{16}$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the given expression, $\left( t-\dfrac{3}{4} \right)\left( t+\dfrac{3}{4} \right)$, is equivalent to \begin{array}{l}\require{cancel} (t)^2-\left( \dfrac{3}{4} \right)^2 \\\\= t^2-\dfrac{9}{16} .\end{array}

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