Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 68

Answer

$25-20t^3+4t^6$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ \left( 5-2t^3 \right)^2 $, is equivalent to \begin{array}{l}\require{cancel} (5)^2+2(5)(-2t^3)+(-2t^3)^2 \\\\= 25-20t^3+4t^6 .\end{array}
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