Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 57

Answer

$t^8+6t^4+9$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ \left( t^4+3 \right)^2 $, is equivalent to \begin{array}{l}\require{cancel} (t^4)^2+2(t^4)\left( 3 \right)+\left( 3 \right)^2 \\\\= t^8+6t^4+9 .\end{array}
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