Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 55

Answer

$a^2-\dfrac{4}{5}a+\dfrac{4}{25}$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ \left( a-\dfrac{2}{5} \right)^2 $, is equivalent to \begin{array}{l}\require{cancel} (a)^2+2(a)\left( -\dfrac{2}{5} \right)+\left( -\dfrac{2}{5} \right)^2 \\\\= a^2-\dfrac{4}{5}a+\dfrac{4}{25} .\end{array}
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