Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 70

Answer

$9p^4-6p^3+p^2$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ \left( 3p^2-p \right)^2 $, is equivalent to \begin{array}{l}\require{cancel} (3p^2)^2+2(3p^2)(-p)+(-p)^2 \\\\= 9p^4-6p^3+p^2 .\end{array}
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