## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$9p^4-6p^3+p^2$
Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $\left( 3p^2-p \right)^2$, is equivalent to \begin{array}{l}\require{cancel} (3p^2)^2+2(3p^2)(-p)+(-p)^2 \\\\= 9p^4-6p^3+p^2 .\end{array}