Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 86: 38

$y=-\dfrac{1}{12}$

Adding $ \dfrac{2}{3} $ to both sides of the given equation, $ -\dfrac{2}{3}+y=-\dfrac{3}{4} $, then, \begin{array}{l} -\dfrac{2}{3}+y+\dfrac{2}{3}=-\dfrac{3}{4}+\dfrac{2}{3} \\\\ y=-\dfrac{3}{4}+\dfrac{2}{3} \\\\ y=-\dfrac{9}{12}+\dfrac{8}{12} \\\\ y=-\dfrac{1}{12} .\end{array}