## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$r=\dfrac{7}{3}$
Adding $-\dfrac{1}{3}$ to both sides of the given equation, $r+\dfrac{1}{3}=\dfrac{8}{3}$, then, \begin{array}{l} r+\dfrac{1}{3}-\dfrac{1}{3}=\dfrac{8}{3}-\dfrac{1}{3} \\\\ r=\dfrac{7}{3} .\end{array}