Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 86: 31



Work Step by Step

Adding $ -\dfrac{1}{3} $ to both sides of the given equation, $ r+\dfrac{1}{3}=\dfrac{8}{3} $, then, \begin{array}{l} r+\dfrac{1}{3}-\dfrac{1}{3}=\dfrac{8}{3}-\dfrac{1}{3} \\\\ r=\dfrac{7}{3} .\end{array}
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