Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 86: 15


a solution

Work Step by Step

Substituting $ x=-2$ to the given equation, $ x+7=3-x $, then \begin{array}{l} -2+7=3-(-2) \\\\ 5=3+2 \\\\ 5=5\text{ (TRUE)} .\end{array} Since the solution above ended with a $\text{ TRUE }$ statement, then the given value of the variable is $\text{ a solution }$ to the given equation.
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