## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Substituting $x= 4$ to the given equation, $6-x=-2$, then \begin{array}{l} 6-4=-2 \\\\ 2=-2 \text{ (FALSE)} .\end{array} Since the solution above ended with a $\text{ FALSE }$ statement, then the given value of the variable is $\text{ NOT a solution }$ to the given equation.