## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Substituting $n=-20$ to the given equation, $4-\dfrac{1}{5}n=8$, then \begin{array}{l} 4-\dfrac{1}{5}(-20)=8 \\\\ 4-(-4)=8 \\\\ 4+4=8 \\\\ 8=8 \text{ (TRUE)} .\end{array} Since the solution above ended with a $\text{ TRUE }$ statement, then the given value of the variable is $\text{ a solution }$ to the given equation.