## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Substituting $t=18$ to the given equation, $\dfrac{2}{3}t=12$, then \begin{array}{l} \dfrac{2}{3}(18)=12 \\\\ 12=12 \text{ (TRUE)} .\end{array} Since the solution above ended with a $\text{ TRUE }$ statement, then the given value of the variable is $\text{ a solution }$ to the given equation.