Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 86: 33



Work Step by Step

Adding $ \dfrac{3}{5} $ to both sides of the given equation, $ x-\dfrac{3}{5}=-\dfrac{7}{10} $, then, \begin{array}{l} x-\dfrac{3}{5}+\dfrac{3}{5}=-\dfrac{7}{10}+\dfrac{3}{5} \\\\ x=-\dfrac{7}{10}+\dfrac{6}{10} \\\\ x=-\dfrac{1}{10} .\end{array}
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