## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set: 14

NOT a solution

#### Work Step by Step

Substituting $t=8$ to the given equation, $\dfrac{2}{3}t=12$, then \begin{array}{l} \dfrac{2}{3}(8)=12 \\\\ \dfrac{16}{3}=12 \text{ (FALSE)} .\end{array} Since the solution above ended with a $\text{ FALSE }$ statement, then the given value of the variable is $\text{ NOT a solution }$ to the given equation.

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