## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x=2$
$\log(2x+1)=\log 5$ First, the solutions must satisfy $2x+1\displaystyle \gt 0\quad \Rightarrow\quad x\gt -\frac{1}{2}\qquad (*)$ in order for the equation to be defined. Apply the principle of logarithmic equality $2x+1=5$ $2x=4$ $x=2\quad$... satisfies (*), and is a valid solution.