Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.6 Solving Exponential Equations and Logarithmic Equations - 12.6 Exercise Set - Page 825: 51



Work Step by Step

$\log(2x+1)=\log 5$ First, the solutions must satisfy $2x+1\displaystyle \gt 0\quad \Rightarrow\quad x\gt -\frac{1}{2}\qquad (*)$ in order for the equation to be defined. Apply the principle of logarithmic equality $2x+1=5$ $2x=4$ $x=2\quad $... satisfies (*), and is a valid solution.
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