## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x=64$
In exponential form, the given logarithmic equation, $\log_2 x =6 ,$ is equivalent to \begin{array}{l}\require{cancel} x=2^6 .\end{array} Hence, the value of the variable that satisfies the given equation is \begin{array}{l}\require{cancel} x=64 .\end{array}