Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.6 Solving Exponential Equations and Logarithmic Equations - 12.6 Exercise Set - Page 825: 18



Work Step by Step

Taking the logarithm of both sides and using the properties of logarithms, the value of the variable that satisfies the given equation, $ 5^{x+2}=15 ,$ is \begin{array}{l}\require{cancel} \log5^{x+2}=\log15 \\\\ (x+2)\log5=\log15 \\\\ x+2=\dfrac{\log15}{\log5} \\\\ x=\dfrac{\log15}{\log5}-2 \\\\ x\approx-0.317 .\end{array}
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