#### Answer

$x\approx2.718$

#### Work Step by Step

In exponential form, the given logarithmic equation, $
\ln x=1
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_e x=1
\\\\
x=e^1
.\end{array}
Hence, the value of the variable that satisfies the given equation is
\begin{array}{l}\require{cancel}
x\approx2.718
.\end{array}