Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.6 Solving Exponential Equations and Logarithmic Equations - 12.6 Exercise Set - Page 825: 17



Work Step by Step

Taking the logarithm of both sides and using the properties of logarithms, the value of the variable that satisfies the given equation, $ 8^{x-3}=19 ,$ is \begin{array}{l}\require{cancel} \log8^{x-3}=\log19 \\\\ (x-3)\log8=\log19 \\\\ x-3=\dfrac{\log19}{\log8} \\\\ x=\dfrac{\log19}{\log8}+3 \\\\ x\approx4.416 .\end{array}
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