#### Answer

$x\approx3.981$

#### Work Step by Step

In exponential form, the given logarithmic equation, $
\log x =0.6
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_{10} x =0.6
\\\\
x=10^{0.6}
.\end{array}
Hence, the value of the variable that satisfies the given equation is
\begin{array}{l}\require{cancel}
x\approx3.981
.\end{array}