Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.6 Solving Exponential Equations and Logarithmic Equations - 12.6 Exercise Set - Page 825: 1



Work Step by Step

No, this is often confused with the argument of a logarithmic function needing to be positive. For example, the equation $ \log_{2}(x+2)=0$ has a negative solution, $x=-1$ (because $2^{0}=1$, and $\log_{2}1=0)$ The negative solution is such that the argument of the logarithm is still positive.
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