## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$t=-3\pm\sqrt{7}$
$(t+3)^{2}=7$ According to the general principle of square roots: For any real number $k$ and any algebraic expression $x$ : $\text{If }x^{2}=k,\text{ then }x=\sqrt{k}\text{ or }x=-\sqrt{k}$. $t+3=\pm\sqrt{7}\qquad$... add $-3$ to both sides. $t=-3\pm\sqrt{7}$