## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Since the discriminant is a positive number that is a perfect square ($10^{2}=100$), there are $2$ rational solutions.
$3x^{2}=4x+7\qquad$....add $-4x-7$ to both sides. $3x^{2}-4x-7=0\qquad$.... $a=3,\ b=-4,\ c=-7$ $b^{2}-4ac\qquad$....substitute $b$ for $-4,\ a$ for $3$ and $c$ for $-7$ $=(-4)^{2}-4\cdot(-7)\cdot 3$ $=16+84$ $=100$