Answer
$y=2$ or $y=\displaystyle \frac{-5}{6}$
Work Step by Step
$ 6y^{2}-7y-10=0\qquad$... solve with the Quadratic formula.
$y=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$
$y=\displaystyle \frac{7\pm\sqrt{49+240}}{12}$
$y=\displaystyle \frac{7\pm\sqrt{289}}{12}$
$y=\displaystyle \frac{7\pm 17}{12}$
$y=\displaystyle \frac{7+17}{12}=\frac{24}{12}=2$ or $y=\displaystyle \frac{7-17}{12}=\frac{-10}{12}=\frac{-5}{6}$
$y=2$ or $y=\displaystyle \frac{-5}{6}$
