## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$y=2$ or $y=\displaystyle \frac{-5}{6}$
$6y^{2}-7y-10=0\qquad$... solve with the Quadratic formula. $y=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ $y=\displaystyle \frac{7\pm\sqrt{49+240}}{12}$ $y=\displaystyle \frac{7\pm\sqrt{289}}{12}$ $y=\displaystyle \frac{7\pm 17}{12}$ $y=\displaystyle \frac{7+17}{12}=\frac{24}{12}=2$ or $y=\displaystyle \frac{7-17}{12}=\frac{-10}{12}=\frac{-5}{6}$ $y=2$ or $y=\displaystyle \frac{-5}{6}$