## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$c=0$ or $c=\displaystyle \frac{7}{16}$
$16c^{2}=7c\qquad$... add $-7c$ to both sides. $16c^{2}-7c=0\qquad$...factor out $c$. $c(16c-7)=0\qquad$...apply the principle of zero products. $16c-7=0$ or $c=0$ $16c=7$ $c=\displaystyle \frac{7}{16}$