Answer
$c=0$ or $c=\displaystyle \frac{7}{16}$
Work Step by Step
$ 16c^{2}=7c\qquad$... add $-7c$ to both sides.
$ 16c^{2}-7c=0\qquad$...factor out $c$.
$ c(16c-7)=0\qquad$...apply the principle of zero products.
$16c-7=0$ or $c=0$
$16c=7$
$c=\displaystyle \frac{7}{16}$
