Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - Mid-Chapter Review - Mixed Review - Page 733: 15


Since the discriminant is a positive number that is not a perfect square, there are $2$ different irrational solutions.

Work Step by Step

$ x^{2}-8x+1=0\qquad$.... $a=1,\ b=-8,\ c=1$ $ b^{2}-4ac\qquad$....substitute $b$ for $-8,\ a$ for $1$ and $c$ for $1$ $=(-8)^{2}-4\cdot 1\cdot 1$ $=64-4$ $=60$
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