Answer
$x=5$ or $x=-6$
Work Step by Step
$(t+4)(t-3)=18\qquad$...apply the FOIL method.
$ t^{2}-3t+4t-12=18\qquad$...simplify.
$ t^{2}+t-12=18\qquad$... add $-18$ to both sides.
$ t^{2}+t-30\qquad$... solve with the Quadratic formula.
$x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$
$x=\displaystyle \frac{-1\pm\sqrt{1+120}}{2}$
$x=\displaystyle \frac{-1\pm\sqrt{121}}{2}$
$x=\displaystyle \frac{-1\pm 11}{2}$
$x=\displaystyle \frac{-1+11}{2}=\frac{10}{2}=5$ or $x=\displaystyle \frac{-1-11}{2}=\frac{-12}{2}=-6$
