Answer
$t=14$ or $t=-14$
Work Step by Step
$ t^{2}-196=0\qquad$...recognize the difference of squares: $a^{2}-b^{2}=(a-b)(a+b)$
$(t-14)(t+14)=0\qquad$...apply the principle of zero products.
$t-14=0$ or $t+14=0$
$t=14$ or $t=-14$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 11 - Quadratic Functions and Equations - Mid-Chapter Review - Mixed Review - Page 733: 4
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