Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - Mid-Chapter Review - Mixed Review - Page 733: 17


Since the discriminant is a negative number, there are $2$ different imaginary-number solutions that are complex conjugates.

Work Step by Step

$ 5x^{2}-x+6=0\qquad$.... $a=5,\ b=-1,\ c=6$ $ b^{2}-4ac\qquad$....substitute $b$ for $-1,\ a$ for $5$ and $c$ for $6$ $=(-1)^{2}-4\cdot 5\cdot 6$ $=1-120$ $=-119$
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