Answer
Since the discriminant is a negative number, there are $2$ different imaginary-number solutions that are complex conjugates.
Work Step by Step
$ 5x^{2}-x+6=0\qquad$.... $a=5,\ b=-1,\ c=6$
$ b^{2}-4ac\qquad$....substitute $b$ for $-1,\ a$ for $5$ and $c$ for $6$
$=(-1)^{2}-4\cdot 5\cdot 6$
$=1-120$
$=-119$
