## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\sqrt[6]{(4a^3b)^5}$
Using the definition of rational exponents which is given by $a^{\frac{m}{n}}=\sqrt[n]{a^m}=\left(\sqrt[n]{a}\right)^m,$ the expression above is equivalent to \begin{array}{l}\require{cancel} (4a^3b)^{5/6} \\\\= \sqrt[6]{(4a^3b)^5} .\end{array}