Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Test: Chapter 10 - Page 695: 2



Work Step by Step

Extracting the factor that is a perfect power of the index results to\begin{array}{l}\require{cancel} \sqrt[3]{-\dfrac{8}{x^6}} \\\\= \sqrt[3]{\left( -\dfrac{2}{x^2} \right)^3} \\\\= -\dfrac{2}{x^2} .\end{array}
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