Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Test: Chapter 10: 27

Answer

$12+2i$

Work Step by Step

Removing the grouping symbols and then combining the real parts and the imaginary parts, the given expression is equivalent to \begin{array}{l}\require{cancel} (9+8i)-(-3+6i) \\\\= 9+8i+3-6i \\\\= (9+3)+(8i-6i) \\\\= 12+2i .\end{array}
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