Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Test: Chapter 10 - Page 695: 24


$\sqrt{17} \text{ units}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the Distance Formula to find the distance between the given points $\left( 3,7 \right)$ and $\left( -1,8 \right)$. $\bf{\text{Solution Details:}}$ With the given points, then $x_1= 3 ,$ $x_2= -1 ,$ $y_1= 7 ,$ and $y_2= 8 .$ Using the Distance Formula which is given by $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2} ,$ then \begin{array}{l}\require{cancel} d=\sqrt{(3-(-1))^2+(7-8)^2} \\\\ d=\sqrt{(3+1)^2+(7-8)^2} \\\\ d=\sqrt{16+1} \\\\ d=\sqrt{17} .\end{array} Hence, the distance is $ \sqrt{17} \text{ units} .$
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