Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Test: Chapter 10 - Page 695: 15

Answer

$6\sqrt{2}$

Work Step by Step

By combining like radicals, the given expression simplifies to \begin{array}{l}\require{cancel} 8\sqrt{2}-2\sqrt{2} \\\\= (8-2)\sqrt{2} \\\\= 6\sqrt{2} .\end{array}
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